A, B and C can complete a work in 5, 7 and 35 hours, respectively. At
Right Answer is: D
Let the total work be 35. Now efficiencies of A, B and C are 7, 5 and 1 respectively.
To complete the work in minimum hours, the most efficient should start the work
So A will start and will be followed by B and C respectively.
So work done in first 7 hours = 13 2 + 7 =33
The remaining work will be done by B
so required time = 2/5 hours
Hence time taken to complete the work in minimum hours = 7 + 2/5 = hours