# A circle is inscribed in ∆ABC, touching AB, BC and AC at the points P,

| A circle is inscribed in ∆ABC, touching AB, BC and AC at the points P, Q and R respectively. If AB – BC = 4 cm, AB – AC = 2 cm and the perimeter of ∆ABC = 32 cm, then PB + AR is equal to :

A.

B.

C. 13 cm

D. 12 cm

### Right Answer is: B

#### SOLUTION

Let

a = 22/3

b = 16/3

PB+AR = b+a = 38/3 cm

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A circle is inscribed in ∆ABC, touching AB, BC and AC at the points P,