# A is 20% less efficient worker than B who is 20% more efficient worker

| A is 20% less efficient worker than B who is 20% more efficient worker than C. If they can complete the whole work in 48 days than in how many days A can complete the whole work alone?

A. 156 days

B. 148 days

C. 158 days

D. 159 days

### Right Answer is: C

#### SOLUTION

Ratio of efficiencies:

A:B = 80:100 = 4:5

B:C = 120:100 = 6:5

Ratio of the efficiencies of A, B and C = 24:30:25

Their cumulative efficiencies = 24 + 30 + 25 = 79

Together they complete work in 48 days

79*48 = 24*(Days required by A to complete)

Required time =

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A is 20% less efficient worker than B who is 20% more efficient worker