A polygon has 5 diagonals and one angle of that polygon is . If the re
Right Answer is: D
let number of sides be n, then
No. of diagonals =
⇒ n(n-5) + 2(n-5) = 0
⇒ (n+2)(n-5) = 0
⇒ n = 5, n = -2
But number of sides cannot equal to -2.
Hence the given polygon is a Pentagon.
One angle of the pentagon is .
Since, the remaining angles are in the ratio 1:2:3:4.
Let the remaining angles be x, 2x, 3x and 4x.
But the sum of interior angles of a pentagon =
According to question
Hence the angles of the pentagon are and .
Hence the size of greatest angles =