# Find the smallest number which when divided by 27, 35 and 42 leaves th

| Find the smallest number which when divided by 27, 35 and 42 leaves the remainder 10, 18 and 25 respectively. Find the sum of the digits of required number.

A. 17

B. 18

C. 19

D. 21

### Right Answer is: C

#### SOLUTION

Since the difference between number and remainder is same –

(27-10) = (35-18) = (42-25) = 17

LCM (27, 35, 42) = 1890

Required Number = 1890 – 17 = 1873

Sum of digits = 1 + 8 + 7 + 3 = 19.

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Find the smallest number which when divided by 27, 35 and 42 leaves th