If a = b = c = 26 then find the value of : Given that, Taking (a+b+c)
Right Answer is: C
Taking (a+b+c) common from Numerator and Denominator:
We know that,
a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca) …………(ii)
Here a = b = c = 26 so (a2 + b2 +c2 – ab – bc – ca) = 0 using this equation (ii) yield
a3 + b3 + c3 = 3abc Putting this in eq.(i):
We get = 3abc/abc = 3.