In ∆ABC, ∠ A = 52 o and O is the orthocenter of the triangle (BO and C
Right Answer is: B
In ∆ ABC,
Since O is orthocenter,
Then, ∠BOC = 180 – A = 180 – 52 = 128°
In ∆ BOC,
P is in-center, Then,
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