In a triangle ∆ ABC , BE and CF are the medians intersect perpendicula
| In a triangle ∆ ABC , BE and CF are the medians intersect perpendicular at P. Find the relation between ?
Right Answer is: A
Let PF = y then PC = 2y ( CF is median) & Let PE = then PB = 2x (BE is median)
In ∆ FPB