In the given figure, from point P two tangents PA and PB are drawn to
Right Answer is: B
Joining OA and OB, we see that triangle OAB is an equilateral triangle because OA = OB = AB = 5cm. And all the angles are 60.
Now PA and PB are perpendicular to OA and OB.
Hence angle PAB and angle PBA = 30º each.
Angle APB = 180 – 30 – 30 = 120º
Since OC and OD are parallel to PA and PB.
Angle COD = angle APB = 120º