In the given figure O is the center of circle. , OA = OD. ABCD is a sq
Right Answer is: D
Join AC and OC. Then,
(Diagonal of the square ABCD)
AD2 = a2 = OA2 + OD2 = 2 ( OA2 )
= 2a2 + a2/2 = 5a2 /2
OC = = radius of the circle
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