# In the given figure, PQR is a triangle and quadrilateral ABCD is inscr

| In the given figure, PQR is a triangle and quadrilateral ABCD is inscribed in it. cm cm, cm, cm, cm, cm and cm. What is the area (in cm2) of the quadrilateral ABCD?

A. (23√21)/4

B. (15√21)/4

C. (17√21)/5

D. (23√21)/5

### Right Answer is: C

#### SOLUTION

PQ = PR = 10

QR = 8, So ∆PQR is an isosceles.

We draw a ⊥ PS to line QR,

Let ∠QPS = θ = ∠RPS

∠PRS = 90 – θ = ∠PQR

PS =

Hence area of ∆PQR

Area of quadrilateral = ar. of ∆PQR – (Ar. of ∆PAB + ∆BRC + ∆DQC)

In ∆ PQS –

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In the given figure, PQR is a triangle and quadrilateral ABCD is inscr