# Number of zeroes at the end of For “n” no. of zeroes at the end of pr

| Number of zeroes at the end of

A. 275

B. 300

C. 350

D. 325

### Right Answer is: C

#### SOLUTION

For “n” no. of zeroes at the end of product, we need exactly “n” combinations of 5 and 2.

Now

In the above expression, we can clearly see that no. of 2’s is greater than number of 5 in the above expression.

So we will just count number of 5 present in the above expression.

Terms with multiple of 5 =

So total number of 5 = 5+10+15+……+50 and extra 25 and 50 for 25^{25} and 50^{50}= 275 + 25 + 50 = 350

Hence number of zeroes will be 350

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