# There are five concentric circle. which are equally distanced from eac

A. 450CM^{2}

B. 350CM^{2}

C. 250CM^{2}

D. 550CM^{2}

### Right Answer is: A

#### SOLUTION

Given side of the inner most square is √72

diagonal of inner most circle is = √72 x √2= √144=12 cm

12 cm is diameter of innermost circle also.

we have to find out the diameter of outermost cirle.

∴distance between the inner most and the outermost circle = 2.25*4 = 9 cm

∴diameter of the outermost circle = 9+ diameter of the innermost circle +9

= 9+12+9 = 30 cm

Since the diameter of the outer most circle = diagonal of the square inscribed in it

∴diagonal of the square inscribed in the outermost circle= 30

side√2 = 30 cm

side = 30/√2 cm

required area = side^{2} =

There are five concentric circle. which are equally distanced from eac